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{"@context":"https://schema.org","@type":"DiscussionForumPosting","headline":"Improper call to `asyncio.Timeout.expired`","articleBody":"# Documentation\r\n\r\nIn [this example](https://docs.python.org/3/library/asyncio-task.html#asyncio.Timeout) for using `asyncio.Timeout`, `expired` is accessed as an attribute, but it should be called as a method.\r\n\r\nI.e. the example should read as:\r\n\r\n```python\r\nasync def main():\r\n    try:\r\n        # We do not know the timeout when starting, so we pass ``None``.\r\n        async with asyncio.timeout(None) as cm:\r\n            # We know the timeout now, so we reschedule it.\r\n            new_deadline = get_running_loop().time() + 10\r\n            cm.reschedule(new_deadline)\r\n\r\n            await long_running_task()\r\n    except TimeoutError:\r\n        pass\r\n\r\n    if cm.expired():  # \u003c---- I CHANGED THIS TO BE A METHOD CALL\r\n        print(\"Looks like we haven't finished on time.\")\r\n```\n\n\u003c!-- gh-linked-prs --\u003e\n### Linked PRs\n* gh-101499\n* gh-101501\n\u003c!-- /gh-linked-prs --\u003e\n","author":{"url":"https://github.com/rsokl","@type":"Person","name":"rsokl"},"datePublished":"2023-02-01T16:57:08.000Z","interactionStatistic":{"@type":"InteractionCounter","interactionType":"https://schema.org/CommentAction","userInteractionCount":0},"url":"https://github.com/101498/cpython/issues/101498"}