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{"@context":"https://schema.org","@type":"DiscussionForumPosting","headline":"First Argument in Function.prototype.call should be optional","articleBody":"### 🕗 Version \u0026 Regression Information\r\nOccurs in the latest Version (4.3.2) and nightly version\r\n\r\n### 💻 Code\r\n[Function.prototype.call](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function/call) combined with [Optional Chaining](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Optional_chaining) is a nice way to only call a method if the method is defined (see [this thread](https://stackoverflow.com/a/65082211/11603006)). \r\n```\r\nfoo?.call()\r\n```\r\n\r\n### 🙁 Actual behavior\r\n\r\nTs complains: `Expected at least 1 arguments, but got 0`  \r\n\r\n### 🙂 Expected behavior\r\n\r\nI expect that this works as the first argument is actually optional according to [Mozilla](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Function/call#using_call_to_invoke_a_function_and_without_specifying_the_first_argument) and own observations. \r\n","author":{"url":"https://github.com/jonath92","@type":"Person","name":"jonath92"},"datePublished":"2021-06-10T06:48:27.000Z","interactionStatistic":{"@type":"InteractionCounter","interactionType":"https://schema.org/CommentAction","userInteractionCount":3},"url":"https://github.com/44530/TypeScript/issues/44530"}