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{"@context":"https://schema.org","@type":"DiscussionForumPosting","headline":"Inconsistent shape handling of parameter c compared to x/y in scatter()","articleBody":"\u003c!--To help us understand and resolve your issue, please fill out the form to the best of your ability.--\u003e\r\n\u003c!--You can feel free to delete the sections that do not apply.--\u003e\r\n\r\n### Bug report\r\n\r\nAs described in https://github.com/matplotlib/matplotlib/pull/11663#pullrequestreview-171359644:\r\n\r\nSomething funny is going on here (I know it was already there before, but still seems worth pointing out): we take x and y of any shapes and flatten them (they just need to have the same size), but `c` has to match either the shape of `x` or `y`, not just the size.\r\n\r\nIn other words the following \"work\" (i.e. perform an implicit ravel()):\r\n```\r\nscatter(np.arange(12).reshape((3, 4)), np.arange(12).reshape((4, 3)), c=np.arange(12).reshape((3, 4)))\r\nscatter(np.arange(12).reshape((3, 4)), np.arange(12).reshape((4, 3)), c=np.arange(12).reshape((4, 3)))\r\n```\r\nbut the following fail:\r\n```\r\nscatter(np.arange(12).reshape((3, 4)), np.arange(12).reshape((4, 3)), c=np.arange(12).reshape((6, 2)))\r\n# and even\r\nscatter(np.arange(12).reshape((3, 4)), np.arange(12).reshape((4, 3)), c=np.arange(12))\r\n```\r\nOf course that last one has the best error message (irony intended):\r\n\r\n\u003e ValueError: 'c' argument has 12 elements, which is not acceptable for use with 'x' with size 12, 'y' with size 12.\r\n\r\n\r\n\r\n","author":{"url":"https://github.com/timhoffm","@type":"Person","name":"timhoffm"},"datePublished":"2018-11-04T12:44:03.000Z","interactionStatistic":{"@type":"InteractionCounter","interactionType":"https://schema.org/CommentAction","userInteractionCount":9},"url":"https://github.com/12735/matplotlib/issues/12735"}