Title: AtomicMarkableReference 不能解决ABA问题 · Issue #626 · Snailclimb/JavaGuide · GitHub
Open Graph Title: AtomicMarkableReference 不能解决ABA问题 · Issue #626 · Snailclimb/JavaGuide
X Title: AtomicMarkableReference 不能解决ABA问题 · Issue #626 · Snailclimb/JavaGuide
Description: /** AtomicMarkableReference则是将一个boolean值作是否有更改的标记,本质就是它的版本号只有两个,true和false, 修改的时候在这两个版本号之间来回切换,这样做并不能解决ABA的问题,只是会降低ABA问题发生的几率而已 @author : mazh @Date : 2020/1/17 14:41 */ public class SolveABAByAtomicMarkableReference { private static Ato...
Open Graph Description: /** AtomicMarkableReference则是将一个boolean值作是否有更改的标记,本质就是它的版本号只有两个,true和false, 修改的时候在这两个版本号之间来回切换,这样做并不能解决ABA的问题,只是会降低ABA问题发生的几率而已 @author : mazh @Date : 2020/1/17 14:41 */ public class SolveABAByAtom...
X Description: /** AtomicMarkableReference则是将一个boolean值作是否有更改的标记,本质就是它的版本号只有两个,true和false, 修改的时候在这两个版本号之间来回切换,这样做并不能解决ABA的问题,只是会降低ABA问题发生的几率而已 @author : mazh @Date : 2020/1/17 14:41 */ public class SolveABAByAtom...
Opengraph URL: https://github.com/Snailclimb/JavaGuide/issues/626
X: @github
Domain: github.com
{"@context":"https://schema.org","@type":"DiscussionForumPosting","headline":"AtomicMarkableReference 不能解决ABA问题","articleBody":"/**\r\n * AtomicMarkableReference则是将一个boolean值作是否有更改的标记,本质就是它的版本号只有两个,true和false,\r\n * 修改的时候在这两个版本号之间来回切换,这样做并不能解决ABA的问题,只是会降低ABA问题发生的几率而已\r\n * @author : mazh\r\n * @date : 2020/1/17 14:41\r\n */\r\npublic class SolveABAByAtomicMarkableReference {\r\n private static AtomicMarkableReference atomicMarkableReference = new AtomicMarkableReference(100,false);\r\n\r\n public static void main(String[] args) {\r\n\r\n Thread refT1 = new Thread(() -\u003e {\r\n try {\r\n TimeUnit.SECONDS.sleep(1);\r\n } catch (InterruptedException e) {\r\n e.printStackTrace();\r\n }\r\n atomicMarkableReference.compareAndSet(100, 101, atomicMarkableReference.isMarked(), !atomicMarkableReference.isMarked());\r\n atomicMarkableReference.compareAndSet(101, 100, atomicMarkableReference.isMarked(), !atomicMarkableReference.isMarked());\r\n });\r\n\r\n Thread refT2 = new Thread(() -\u003e {\r\n boolean marked = atomicMarkableReference.isMarked();\r\n try {\r\n TimeUnit.SECONDS.sleep(2);\r\n } catch (InterruptedException e) {\r\n e.printStackTrace();\r\n }\r\n boolean c3 = atomicMarkableReference.compareAndSet(100, 101, marked, !marked);\r\n System.out.println(c3); // 返回true,实际应该返回false\r\n });\r\n\r\n refT1.start();\r\n refT2.start();\r\n }\r\n}\r\n\r\n个人理解是这样,不知是否正确?\r\n","author":{"url":"https://github.com/itmaaa","@type":"Person","name":"itmaaa"},"datePublished":"2020-01-17T06:57:33.000Z","interactionStatistic":{"@type":"InteractionCounter","interactionType":"https://schema.org/CommentAction","userInteractionCount":8},"url":"https://github.com/626/JavaGuide/issues/626"}
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| og:image:alt | /** AtomicMarkableReference则是将一个boolean值作是否有更改的标记,本质就是它的版本号只有两个,true和false, 修改的时候在这两个版本号之间来回切换,这样做并不能解决ABA的问题,只是会降低ABA问题发生的几率而已 @author : mazh @Date : 2020/1/17 14:41 */ public class SolveABAByAtom... |
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