René's URL Explorer Experiment

{"@context":"https://schema.org","@type":"DiscussionForumPosting","headline":"angular请求多个接口之后再统一返回数据","articleBody":"### angular请求多个接口之后再统一返回数据\r\n**promise()方法**\r\n\r\n循环组成数组，拼接\r\n```\r\nvar queryApi = [];\r\nangular.forEach(res,function(data,index,array){\r\n\tvar ajaxApi = $.ajax(\"...\");\r\n\tqueryApi.push(ajaxApi)\r\n})\r\nPromise.all(queryApi).then(function(res){\r\n\t...\r\n})\r\n```\r\n\r\n### 异步请求多个接口：\r\n**第一种：promise()**\r\n```\r\nPromise.all([p1, p2, p3]).then(function (results) { \r\n    console.log(results);  // [1, 2, 3] \r\n});\r\n```\r\n**第二种：when()**\r\n```\r\n$.when([$.ajax('/request1'), $.ajax('/request2'), $.ajax('/request3')]).done(function (data) { \r\n     console.log('第一个ajax请求',data[0]); \r\n     console.log('第二个ajax请求',data[1]); \r\n     console.log('第三个ajax请求',data[2]); \r\n});\r\n```\r\n之后触发数据更新 $apply()","author":{"url":"https://github.com/Narutocc","@type":"Person","name":"Narutocc"},"datePublished":"2018-04-11T07:00:12.000Z","interactionStatistic":{"@type":"InteractionCounter","interactionType":"https://schema.org/CommentAction","userInteractionCount":0},"url":"https://github.com/18/angular/issues/18"}