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Title: GitHub - FlyingDance520/Java-Interview: 经历BAT面试后总结的【高级Java后台开发面试指南】，纯净干货无废话，针对高频面试点 · GitHub

Open Graph Title: GitHub - FlyingDance520/Java-Interview: 经历BAT面试后总结的【高级Java后台开发面试指南】，纯净干货无废话，针对高频面试点

X Title: GitHub - FlyingDance520/Java-Interview: 经历BAT面试后总结的【高级Java后台开发面试指南】，纯净干货无废话，针对高频面试点

Description: 经历BAT面试后总结的【高级Java后台开发面试指南】，纯净干货无废话，针对高频面试点. Contribute to FlyingDance520/Java-Interview development by creating an account on GitHub.

Open Graph Description: 经历BAT面试后总结的【高级Java后台开发面试指南】，纯净干货无废话，针对高频面试点. Contribute to FlyingDance520/Java-Interview development by creating an account on GitHub.

X Description: 经历BAT面试后总结的【高级Java后台开发面试指南】，纯净干货无废话，针对高频面试点. Contribute to FlyingDance520/Java-Interview development by creating an account on GitHub.

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https://github.com/FlyingDance520/Java-Interview#web框架数据库
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https://github.com/FlyingDance520/Java-Interview#通用基础
操作系统https://github.com/xbox1994/Java-Interview/blob/master/MD/%E9%80%9A%E7%94%A8%E5%9F%BA%E7%A1%80-%E6%93%8D%E4%BD%9C%E7%B3%BB%E7%BB%9F.md
网络通信协议https://github.com/xbox1994/Java-Interview/blob/master/MD/%E9%80%9A%E7%94%A8%E5%9F%BA%E7%A1%80-%E7%BD%91%E7%BB%9C%E9%80%9A%E4%BF%A1%E5%8D%8F%E8%AE%AE.md
排序算法https://github.com/xbox1994/Java-Interview/blob/master/MD/%E9%80%9A%E7%94%A8%E5%9F%BA%E7%A1%80-%E6%8E%92%E5%BA%8F%E7%AE%97%E6%B3%95.md
常用设计模式https://github.com/xbox1994/Java-Interview/blob/master/MD/%E9%80%9A%E7%94%A8%E5%9F%BA%E7%A1%80-%E8%AE%BE%E8%AE%A1%E6%A8%A1%E5%BC%8F.md
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https://github.com/FlyingDance520/Java-Interview#分布式
CAP理论https://github.com/xbox1994/Java-Interview/blob/master/MD/%E5%88%86%E5%B8%83%E5%BC%8F-CAP%E7%90%86%E8%AE%BA.md
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ID生成方式https://github.com/xbox1994/Java-Interview/blob/master/MD/%E5%88%86%E5%B8%83%E5%BC%8F-ID%E7%94%9F%E6%88%90%E6%96%B9%E5%BC%8F.md
一致性hashhttps://github.com/xbox1994/Java-Interview/blob/master/MD/%E5%88%86%E5%B8%83%E5%BC%8F-%E4%B8%80%E8%87%B4%E6%80%A7hash.md
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https://github.com/FlyingDance520/Java-Interview#微服务
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https://github.com/FlyingDance520/Java-Interview#算法
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二叉树-递归-二叉树反转https://github.com/xbox1994/Java-Interview/blob/master/MD/%E7%AE%97%E6%B3%95-%E4%BA%8C%E5%8F%89%E6%A0%91-%E9%80%92%E5%BD%92-%E4%BA%8C%E5%8F%89%E6%A0%91%E5%8F%8D%E8%BD%AC.md
二叉树-递归-多叉树中最长的连续序列https://github.com/xbox1994/Java-Interview/blob/master/MD/%E7%AE%97%E6%B3%95-%E4%BA%8C%E5%8F%89%E6%A0%91-%E5%A4%9A%E5%8F%89%E6%A0%91%E4%B8%AD%E6%9C%80%E9%95%BF%E7%9A%84%E8%BF%9E%E7%BB%AD%E5%BA%8F%E5%88%97.md
动态规划-连续子数组最大和https://github.com/xbox1994/Java-Interview/blob/master/MD/%E7%AE%97%E6%B3%95-%E5%8A%A8%E6%80%81%E8%A7%84%E5%88%92-%E8%BF%9E%E7%BB%AD%E5%AD%90%E6%95%B0%E7%BB%84%E6%9C%80%E5%A4%A7%E5%92%8C.md
数据结构-LRU淘汰算法https://github.com/xbox1994/Java-Interview/blob/master/MD/%E7%AE%97%E6%B3%95-%E6%95%B0%E6%8D%AE%E7%BB%93%E6%9E%84-LRU%E6%B7%98%E6%B1%B0%E7%AE%97%E6%B3%95.md
其他-二十进制相加https://github.com/xbox1994/Java-Interview/blob/master/MD/%E7%AE%97%E6%B3%95-%E5%85%B6%E4%BB%96-%E4%BA%8C%E5%8D%81%E8%BF%9B%E5%88%B6%E7%9B%B8%E5%8A%A0.md
有序数组中位数https://leetcode-cn.com/problems/median-of-two-sorted-arrays/solution/xun-zhao-liang-ge-you-xu-shu-zu-de-zhong-wei-s-114/
数组中的k个最小值https://leetcode-cn.com/problems/zui-xiao-de-kge-shu-lcof/solution/zui-xiao-de-kge-shu-by-leetcode-solution/
https://github.com/FlyingDance520/Java-Interview#项目举例
秒杀架构https://github.com/xbox1994/Java-Interview/blob/master/MD/%E7%A7%92%E6%9D%80%E6%9E%B6%E6%9E%84.md
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系统设计-高并发抢红包https://github.com/xbox1994/Java-Interview/blob/master/MD/%E7%B3%BB%E7%BB%9F%E8%AE%BE%E8%AE%A1-%E9%AB%98%E5%B9%B6%E5%8F%91%E6%8A%A2%E7%BA%A2%E5%8C%85.md
系统设计-答题套路https://github.com/donnemartin/system-design-primer/blob/master/README-zh-Hans.md#%E5%A6%82%E4%BD%95%E5%A4%84%E7%90%86%E4%B8%80%E4%B8%AA%E7%B3%BB%E7%BB%9F%E8%AE%BE%E8%AE%A1%E7%9A%84%E9%9D%A2%E8%AF%95%E9%A2%98
系统设计-在AWS上扩展到数百万用户的系统https://www.wangtianyi.top/blog/2019/03/06/zai-awsshang-kuo-zhan-dao-shu-bai-mo-yong-hu-de-xi-tong/?utm_source=github&utm_medium=github
系统设计-从面试者角度设计一个系统设计题http://www.wangtianyi.top/blog/2018/08/31/xi-tong-she-ji-mian-shi-ti-zong-he-kao-cha-mian-shi-zhe-de-da-zhao/?utm_source=github&utm_medium=github
https://github.com/FlyingDance520/Java-Interview#智力题
概率p输出1，概率1-p输出0，等概率输出0和1https://blog.csdn.net/qq_29108585/article/details/60765640
判断点是否在多边形内部https://www.cnblogs.com/muyefeiwu/p/11260366.html
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